\documentclass[12pt , a4paper]{report}
\usepackage[all]{xy}
\usepackage{amsthm, amssymb, amsmath,amsfonts,fancyhdr,color,xspace,hyperref,latexsym,amscd,tikz}
%\usepackage{amsthm, amssymb, amsmath,amsfonts,fancyhdr,color,xspace,hyperref,latexsym,amscd,tikz} 
%\usepackage{glossaries}
\usepackage[twoside,top=26mm, bottom=21mm, left=60mm, right=0.5mm]{geometry}
%\fancyhead{} 
%\fancyhead[L]{\slshape \rightmark}
%\fancyhead[R]{\slshape \leftmark}
\usepackage{graphicx}
\usepackage[pagebackref=false,colorlinks,linkcolor=blue,citecolor=magenta]{hyperref}
\pagestyle{fancy}
\usepackage{graphicx}
\fancyfoot{} 
\fancyfoot[C]{\thepage}
\renewcommand{\headrulewidth}{0.6pt}
\usepackage{xepersian}
\settextfont[Scale=1.2]{B Nazanin}
\setlatintextfont[ExternalLocation,BoldFont={lmroman10-bold},BoldItalicFont={lmroman10-bolditalic},ItalicFont={lmroman10-italic}]{lmroman10-regular}
\setdigitfont[Scale=1.2]{B Nazanin}
\linespread{2}
\defpersianfont\nastaliq[Scale=1]{IranNastaliq}
\linespread{2}
\usepackage[nottoc]{tocbibind}
\include{references}



\theoremstyle{definition}\newtheorem{de}{تعریف}[section]
\theoremstyle{plain}\newtheorem{thh}[de]{قضیه}
\theoremstyle{plain}\newtheorem{pr}[de]{گزاره}
\theoremstyle{plain}\newtheorem{rem}[de]{نکته}
\theoremstyle{plain}\newtheorem{lee}[de]{لم}
\theoremstyle{plain}\newtheorem{cor}[de]{نتیجه}
\theoremstyle{plain}\newtheorem{coro}[de]{فرع}
\theoremstyle{definition}\newtheorem{exa}[de]{مثال}
\theoremstyle{plain}\newtheorem{rema}[de]{تذکر}
\theoremstyle{plain}\newtheorem{qu}[de]{سؤال}
%renewcommand\proofname{\textbf{برهان}}
\renewcommand{\bibname}{\textbf{مراجع}}

\newcommand\persiangloss[2]{#1\dotfill\lr{#2}\\}
% دستوری برای تعریف واژه‌نامه فارسی به انگلیسی 
\newcommand\englishgloss[2]{#2\dotfill\lr{#1}\\}

\pagenumbering{arabic}
%\makeglossaries

%\tableofcontents


\begin{tabular}{cccc|c} 
$f$ & $j$ & 1 & 0 & $\cdot $ \\ 
\hline 
0 & 0 & 0 & 0 & 0 \\ 
1 & 1 & 1 & 1 & 1 \\ 
$f$ & $j$ & 1 & 0 & $j$ \\ 
$j$ & $f$ & 0 & 1 & $f$ \\ 
\end{tabular} 
\qquad
\begin{tabular}{cccc|c}
$f$ & $j$ & 1 & 0 &$ \bullet $\\ 
\hline 
0 & 0 & 0 & 0 & 0 \\ 
$f$ & $j$ & 1 & 0 & 1 \\ 
0 & $j$ & $j$ & 0 & $j$ \\ 
$f$ & 0 & $f$ & 0 & $f$ \\ 
\end{tabular}