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\begin{align}\label{Eq}
&\left( {\begin{array}{*{20}{c}}
	{{d_1}}&{{d_2}}\\
	{{d_3}}&{{d_4}}
	\end{array}} \right)\left\{ \begin{array}{l}
A\\
B
\end{array} \right\} =  - {\omega ^2}{X_b}\left\{ \begin{array}{l}
{F_1}\\
{F_2}
\end{array} \right\}\nonumber\\[3mm]
&\left[ D \right] = \left( {\begin{array}{*{20}{c}}
	{{d_1}}&{{d_2}}\\
	{{d_3}}&{{d_4}}
	\end{array}} \right)\nonumber\\[3.3mm]
&{d_1} =  - {M_1}{\omega ^2} + {C_1}i\omega  + {K_1}\nonumber\\[3mm]
&{d_2} = {K_c} + {C_2}i\omega \nonumber\\[3mm]
&{d_3} = {K_c} + {C_3}i\omega \nonumber\\[3mm]
&{d_4} =  - {M_2}{\omega ^2} + {C_4}i\omega  + {K_2} + \frac{{i\omega \,v{c_2}^2}}{{c{p_2}\,i\omega \, + \,\frac{1}{{R{l_2}}}}}\nonumber\\[3mm]
&{F_1} =  - \int_0^L {{m_1}} \phi (x){\mkern 1mu} dx - M{t_1}{\mkern 1mu} \phi (L)\nonumber\\[3.3mm]
&{F_2} =  - \int_0^L {{m_2}} \psi (x)dx - M{t_2}\psi (L)
\end{align}


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